Calculate $\Delta$G° for the oxidation of 3 moles of copper by nitric acid. Cu 2+ (aq)+ 2e - Cu(s);E° = 0.34 V NO 3 - (aq)+ 4H + (aq)+ 3e - NO(g)+ 2H 2 O(l);E° = 0.957 V

The Answer of Calculate $\Delta$G° for the oxidation of 3 moles of copper by nitric acid. Cu 2+ (aq)+ 2e - Cu(s);E° = 0.34 V NO 3 - (aq)+ 4H + (aq)+ 3e - NO(g)+ 2H 2 O(l);E° = 0.957 V

Calculate $\Delta$G° for the oxidation of 3 moles of copper by nitric acid. Cu 2+ (aq)+ 2e - Cu(s);E° = 0.34 V NO 3 - (aq)+ 4H + (aq)+ 3e - NO(g)+ 2H 2 O(l);E° = 0.957 V

The Answer of Calculate $\Delta$G° for the oxidation of 3 moles of copper by nitric acid. Cu 2+ (aq)+ 2e - Cu(s);E° = 0.34 V NO 3 - (aq)+ 4H + (aq)+ 3e - NO(g)+ 2H 2 O(l);E° = 0.957 V

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Calculate $\Delta$ G° for the Oxidation of 3 Moles of Copper by Copper

Question 52

Multiple Choice

Calculate $\Delta$ G° for the oxidation of 3 moles of copper by nitric acid.
Cu²⁺(aq) + 2e^- $Calculate \Delta G° for the oxidation of 3 moles of copper by nitric acid. Cu2+(aq) + 2e- Cu(s) ;E° = 0.34 V NO3-(aq) + 4H+(aq) + 3e- NO(g) + 2H2O(l) ;E° = 0.957 V A) -120 kJ B) -180 kJ C) -240 kJ D) -300 kJ E) -360 kJ$
Cu(s) ;E° = 0.34 V
NO₃^-(aq) + 4H⁺(aq) + 3e^- $Calculate \Delta G° for the oxidation of 3 moles of copper by nitric acid. Cu2+(aq) + 2e- Cu(s) ;E° = 0.34 V NO3-(aq) + 4H+(aq) + 3e- NO(g) + 2H2O(l) ;E° = 0.957 V A) -120 kJ B) -180 kJ C) -240 kJ D) -300 kJ E) -360 kJ$
NO(g) + 2H₂O(l) ;E° = 0.957 V