Suppose it took 108 joules of energy to raise a bar of gold from 25.0°C to 29.7°C.Given that the specific heat capacity of gold is 0.128 J/g∙°C,what is the mass (in grams)of the bar of gold?

Question

Quizplus · Accepted Answer

We can use the formula:
q = m*c*ΔT

where q is the heat transferred, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

Rearranging the formula, we get:
m = q/(c*ΔT)

Substituting the given values, we get:
m = 108 J / (0.128 J/g∙°C * (29.7°C - 25.0°C))
m = 1.8 × 10¹² g

Therefore, the mass of the bar of gold is 1.8 × 10¹² g, which is closest to option B.

Suppose It Took 108 Joules of Energy to Raise a Bar