What is the final temperature of 25.0 grams of water at 22.0°C after it absorbs 454 J of heat?

Question

Quizplus · Accepted Answer

First, we need to use the equation: q = mCΔT, where q is the heat absorbed, m is the mass of water, C is the specific heat capacity of water, and ΔT is the change in temperature. We can rearrange the equation to solve for ΔT: ΔT = q / (mC). Plugging in the given values, we get: ΔT = 454 J / ((25.0 g)(4.18 J/g°C)) = 4.29°C. Therefore, the final temperature is 22.0°C + 4.29°C = 26.3°C, which corresponds to choice C.

What Is the Final Temperature of 25