What is the final volume of a 500.0 mL gas container that increased in temperature from 299 K to 333 K while the pressure increased from 1.00 atm to 1.54 atm?

Question

Quizplus · Accepted Answer

Using the combined gas law:
(P1V1)/T1=(P2V2)/T2
where P1=1.00 atm, V1=500.0 mL, T1=299 K, P2=1.54 atm, T2=333 K, and solving for V2:
V2=(P1V1T2)/(P2T1)=(1.00 atm)(500.0 mL)(333 K)/(1.54 atm)(299 K)=0.362 L
Therefore, the final volume is 0.362 L.

What Is the Final Volume of a 500