What is the final pressure (atm)of a 3.05 L system initially at 724 mm Hg and 298 K that is compressed to a final volume of 2.51 L at 273 K?

Name: What is the final pressure (atm)of a 3.05 L system initially at 724 mm Hg and 298 K that is compressed to a final volume of 2.51 L at 273 K?
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Quizplus · Accepted Answer

Using the combined gas law, we can solve for the final pressure:P1V1/T1 = P2V2/T2(724 mmHg)(3.05 L)/(298 K) = P2(2.51 L)/(273 K)P2 = 860 mmHg = 1.13 atm

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