What is the heat of vaporization(kJ/mol)if it takes 3,452 J of heat to completely vaporize 2.68 moles of the liquid at its boiling point?

Name: What is the heat of vaporization(kJ/mol)if it takes 3,452 J of heat to completely vaporize 2.68 moles of the liquid at its boiling point?
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Quizplus · Accepted Answer

The heat of vaporization is calculated by dividing the total heat by the number of moles: 3,452 J / 2.68 mol = 1,288 J/mol, which is equivalent to 1.29 kJ/mol.

What Is the Heat of Vaporization(kJ/mol)if It Takes 3,452 J