How many joules of heat are needed to completely vaporize 24.40 grams of water at its boiling point?
Given ΔH_vap = 40.6 kJ/mol

Question

How many joules of heat are needed to completely vaporize 24.40 grams of water at its boiling point? Given ΔH_vap = 40.6 kJ/mol

Quizplus · Accepted Answer

To find the heat needed, first convert grams of water to moles (24.40 g / 18.015 g/mol = 1.354 mol). Then, multiply by the heat of vaporization (1.354 mol * 40.6 kJ/mol = 54.97 kJ). Convert to joules (54.97 kJ * 1000 J/kJ = 54970 J), which is approximately 5.50 x 10^4 J.

How Many Joules of Heat Are Needed to Completely Vaporize