How many grams of KCl are present in 75.0 mL of 2.10 M KCl?

Name: How many grams of KCl are present in 75.0 mL of 2.10 M KCl?
Brand: Quizplus
Rating: 4.8 (64 reviews)

Question

Quizplus · Accepted Answer

First, use the formula:

moles = concentration x volume

to calculate the moles of KCl present in 75.0 mL of 2.10 M KCl:

moles = 2.10 mol/L x 0.0750 L = 0.1575 moles

Next, use the molar mass of KCl (74.55 g/mol) to convert moles to grams:

grams = moles x molar mass = 0.1575 moles x 74.55 g/mol = 11.7 g

Therefore, the answer is D: 11.7.

How Many Grams of KCl Are Present in 75