Exactly 17.0 mL of a H₂SO₄ solution was required to neutralize 45.0 mL of 0.235 M NaOH.What was the concentration of the H₂SO₄ solution?
GIVEN: H₂SO₄ (aq) + 2NaOH (aq) → 2H₂O (l) + Na₂SO₄ (aq)

Question

Quizplus · Accepted Answer

The balanced equation shows that 1 mole of H2SO4 reacts with 2 moles of NaOH. Using the formula M1V1 = M2V2/2, where M1 and V1 are the molarity and volume of H2SO4, and M2 and V2 are the molarity and volume of NaOH, we find M1 = (0.235 M * 45.0 mL) / (2 * 17.0 mL) = 0.311 M.