For the reaction S₂F₆ (g)⇌ 2SF₂ (g)+ F₂ (g),the equilibrium concentrations are as follows: [S₂F₆] = 0.000430 M,[SF₂] = 2.08 M,[F₂] = 1.32 M.The equilibrium constant is:

Question

Quizplus · Accepted Answer

The equilibrium constant expression for the given reaction is: Kc = ([SF₂]²[F₂])/[S₂F₆] Substituting the given equilibrium concentrations, we get: Kc = (2.08)²(1.32)/(0.000430) = 1.33 × 10^14 Therefore, the best choice is option D.

For the Reaction S2F6 (G)⇌ 2SF2 (G)+ F2 (G),the Equilibrium

For the Reaction S₂F₆ (G)⇌ 2SF₂ (G)+ F₂ (G),the Equilibrium