For the reaction Ag₂S(s)⇌ 2 Ag⁺ (aq)+ S^2- (aq),K_eq = 2.4 × 10^-4 and the equilibrium concentration of silver ion is [Ag⁺] = 2.5 × 10^-¹ M.What is [S^2-] at equilibrium?

Question

Quizplus · Accepted Answer

The equilibrium constant expression for the given reaction is:K_eq = [Ag⁺]²[S^2-]Substituting the given values into the expression, we get:2.4 × 10^-4 = (2.5 × 10^-1)²[S^2-]Solving for [S^2-], we get:[S^2-] = 0.0038 MTherefore, the correct answer is A.

For the Reaction Ag2S(s)⇌ 2 Ag+ (Aq)+ S2- (Aq),Keq =

For the Reaction Ag₂S(s)⇌ 2 Ag⁺ (Aq)+ S^2- (Aq),K_eq =