What is the temperature (°C)of 2.48 moles of gas stored in a
Container at
?
(R= 0.0821 L atm/ mol K)

Question

What is the temperature (°C)of 2.48 moles of gas stored in a 
Container at 
?
(R= 0.0821 L atm/ mol K)

Quizplus · Accepted Answer

We can use the Ideal Gas Law, PV=nRT, to solve for the temperature. However, we are not given the pressure or volume of the gas. Instead, we can use the fact that the container is at STP (standard temperature and pressure), which is 0°C (or 273 K) and 1 atm. At STP, 1 mole of gas occupies 22.4 L. Therefore, since we have 2.48 moles of gas in a container that can hold 22.4 L, the gas is likely compressed (under pressure) and its volume is less than 22.4 L. However, we don't need to know the actual volume to solve for the temperature. We can use the fact that at STP, the pressure and volume are fixed, and the only variable is temperature.

We can rearrange the Ideal Gas Law to solve for temperature: T = (PV) / (nR). At STP, P = 1 atm, V = 22.4 L, n = 2.48 mol, and R = 0.0821 L atm / mol K. Plugging these values in, we get:

T = (1 atm * 22.4 L) / (2.48 mol * 0.0821 L atm / mol K)
T = 273 K

Note that we don't need to convert the temperature to Celsius since we were asked for the temperature in K. Therefore, the answer is (C) 29 K.

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