What is the concentration of sodium chloride in the final solution if
Of
BaC
Completely reacts and the total volume of the reaction is
,given the reaction:
Ba
(aq)+ N
S
(aq)→ BaS
(s)+ 2NaCl (aq)

Question

What is the concentration of sodium chloride in the final solution if 
Of 
BaC 
Completely reacts and the total volume of the reaction is 
,given the reaction:
Ba 
(aq)+ N 
S 
(aq)→ BaS 
(s)+ 2NaCl (aq)

Quizplus · Accepted Answer

The balanced chemical equation shows that 1 mole of barium chloride reacts with 1 mole of sodium chloride to produce 1 mole of barium sulfide. Therefore, the number of moles of sodium chloride is equal to the number of moles of barium chloride used in the reaction. The number of moles of barium chloride can be calculated using the volume and concentration given:

moles of BaCl2 = volume (in L) x concentration (in mol/L) = 0.050 L x 0.2 mol/L = 0.01 mol

Therefore, there are 0.01 moles of NaCl in the reaction. The total volume of the reaction is not given, so we cannot directly calculate the concentration of NaCl in the final solution. However, since the reaction is complete, all the barium chloride has reacted to form barium sulfide and all the sodium chloride has remained in solution. Therefore, the final volume of the solution is equal to the initial volume of barium chloride solution, which is 0.050 L. The concentration of NaCl in the final solution is:

concentration of NaCl = moles of NaCl / volume of solution = 0.01 mol / 0.050 L = 0.2 mol/L

This is the concentration of NaCl in the initial barium chloride solution, so we need to take into account that the volume has doubled due to the addition of NaCl. Therefore, the final concentration of NaCl is:

final concentration of NaCl = concentration of NaCl in initial solution / 2 = 0.2 mol/L / 2 = 0.1 mol/L

The final concentration of NaCl is 0.1 mol/L, which is equivalent to 0.0519 g/mL. Therefore, the best choice is C.

What Is the Concentration of Sodium Chloride in the Final