Find the initial velocity for an enzymatic reaction when V_max = 6.5 × 10^-5 mol•sec^-1,[S] = 3.0 × 10^-3 M,K_M = 4.5 × 10^-3 M and the enzyme concentration at time zero is 1.5 × 10^-2 $\mu$M. A)3)9 × 10^-5 mol•sec^-1 B)2)6 × 10^-5 mol•sec^-1 C)1)4 × 10^-2 mol•sec^-1 D)8)7 × 10^-3 mol•sec^-1 E)Not enough information is given to make this calculation.

Question

Quizplus · Accepted Answer

The initial velocity can be calculated using the Michaelis-Menten equation: V0 = (V_max * [S])/(K_M + [S]) Plugging in the given values: V0 = (6.5 × 10^-5 mol•sec^-1) * (3.0 × 10^-3 M) / ((4.5 × 10^-3 M) + (3.0 × 10^-3 M)) V0 = 2.6 × 10^-5 mol•sec^-1 Therefore, the initial velocity is 2.6 × 10^-5 mol•sec^-1, corresponding to choice B.

Find the Initial Velocity for an Enzymatic Reaction When Vmax μ\muμ

Find the Initial Velocity for an Enzymatic Reaction When V_max $\mu$