Exhibit 8-1
For the following questions, consider the equation below. Zinc will react with a solution of hydrochloric acid to produce hydrogen gas:
Zn(s) + 2 HCl(aq) $\to$ ZnCl₂(s) + H₂(g)
-Refer to Exhibit 8-1. What weight of ZnCl₂ will be produced from 1.00 mol of Zn?

Question

Exhibit 8-1
For the following questions, consider the equation below. Zinc will react with a solution of hydrochloric acid to produce hydrogen gas:
Zn(s) + 2 HCl(aq)

\to

ZnCl₂(s) + H₂(g)
-Refer to Exhibit 8-1. What weight of ZnCl₂ will be produced from 1.00 mol of Zn?

Quizplus · Accepted Answer

From the balanced equation, we can see that 1 mole of Zn reacts with 2 moles of HCl to produce 1 mole of ZnCl2 and 1 mole of H2. Therefore, if 1.00 mol of Zn reacts, then 1.00 mol of ZnCl2 will be produced.

To calculate the weight of ZnCl2 produced, we need to use its molar mass, which is found by adding the masses of one zinc atom and two chlorine atoms:

Molar mass of ZnCl2 = 65.38 g/mol

Therefore, the weight of ZnCl2 produced from 1.00 mol of Zn is:

1.00 mol Zn × 65.38 g/mol ZnCl2 = 65.38 g ZnCl2

Round to the nearest tenth, gives us the answer C: 136 g.

Exhibit 8-1 for the Following Questions, Consider the Equation Below →\to→

Exhibit 8-1
for the Following Questions, Consider the Equation Below $\to$