What is the result when the following code is run?
Double x = 1;
Double y = 1;
Int i = 0;
Do
{
Y = x / 2;
X = x + y;
I = i + 1;
}
While (x

Question

What is the result when the following code is run?
Double x = 1;
Double y = 1;
Int i = 0;
Do
{
Y = x / 2;
X = x + y;
I = i + 1;
}
While (x < 2.5);
System.out.print(i + " ");
A) 1
B) 2
C) 3
D) 4

Quizplus · Accepted Answer

The code creates two variables, x and y, both with initial value of 1, and an integer variable i with initial value of 0. It then enters a do-while loop, where y is assigned the value of x divided by 2, x is assigned the value of x plus y, and i is incremented by 1. The loop condition checks if x is less than 2.5. Since the initial value of x is 1, the loop will run as long as x is less than 2.5.

The first iteration of the loop will result in x being assigned the value of 1.5 and i being assigned the value of 1. In the second iteration, x will be assigned the value of 2.25 and i will be assigned the value of 2. In the third iteration, x will be assigned the value of 3.375 and i will be assigned the value of 3. Since x is now greater than 2.5, the loop will terminate.

After the loop, the code prints the value of i, which is 3. Therefore, the correct answer is C.

What Is the Result When the Following Code Is Run