What is the output of the following code snippet?
Public static void doubleAmount(int intvalue)
{
Intvalue = 2 * intvalue;
}
Public static void main(String[] args)
{
Int principalAmt = 2000;
System.out.println(doubleAmount(principalAmt));
}
A) 2000
B) 4000
C) 0
D) Compilation error

Question

Quizplus · Accepted Answer

There are two errors in this code.

Firstly, the method doubleAmount() is declared as void, which means it does not return any value. Therefore, it cannot be printed using System.out.println().

Secondly, the variable name in the method signature (intvalue) does not match the variable name used in the method body (Intvalue). This will cause a compilation error.

What Is the Output of the Following Code Snippet