Given the following code, what is the output?
public class MysteriousClass
{
public static void main(String[] args)
{
int i = 20;
int b = m2(i);
System.out.println(b + i);
}
public static int m1(int i)
{
int n = 0;
while (n * n

Question

Given the following code, what is the output?
public class MysteriousClass
{
public static void main(String[] args)
{
int i = 20;
int b = m2(i);
System.out.println(b + i);
}
public static int m1(int i)
{
int n = 0;
while (n * n <= i)
{
n++;
}
return n - 1;
}
public static int m2(int a) {
int b = 0;
for (int n = 0; n < a; n++)
{
Int i = m1(n);
b = b + i;
}
return b;
}
}
A) 50
B) 60
C) 70
D) 80

Quizplus · Accepted Answer

The method m1 calculates the integer square root of n. The method m2 sums these square roots for all numbers from 0 to 19. The sum of integer square roots from 0 to 19 is 50, and adding i (20) gives 70.

Given the Following Code, What Is the Output