What is the output of the following code snippet?
Public static void main(String[] args)
{
Int gvar = 0;
Gvar = gvar + 10;
If (gvar 0)
{
Int lvar = gvar + 1;
}
System.out.println(lvar);
}
A) 1
B) 10
C) 11
D) No output due to compilation error

Question

What is the output of the following code snippet?
Public static void main(String[] args)
{
Int gvar = 0;
Gvar = gvar + 10;
If (gvar > 0)
{
Int lvar = gvar + 1;
}
System.out.println(lvar);
}
A) 1
B) 10
C) 11
D) No output due to compilation error

Quizplus · Accepted Answer

The code will result in a compilation error at the line `System.out.println(lvar);` because `lvar` is declared inside the if statement and is not accessible outside of it. Therefore, it is out of scope and cannot be printed. Additionally, there is a syntax error where `Int` should be `int`, as Java is a case-sensitive language.

What Is the Output of the Following Code Snippet