Consider the following code snippet:
Public class Inventory implements Measurable
{
Private int onHandCount;
) . .
Double getMeasure();
{
Return onHandCount;
}
}
Assume that getMeasure() is a method in the interface Measurable. The compiler complains that the getMeasure method has a weaker access level than the Measurable interface. Why?
A) All of the methods in a class have a default access level of package access, while the methods of an interface have a default access level of private.
B) All of the methods in a class have a default access level of package access, while the methods of an interface have a default access level of public.
C) The variable onHandCount was not declared with public access.
D) The getMeasure method was declared as private in the Measurable interface.

Question

Quizplus · Accepted Answer

In Java, all methods in a class have a default access level of package access, which means they are only accessible within the same package. However, all methods in an interface have a default access level of public, which means they can be accessed from any package. Since the getMeasure method in the Inventory class is attempting to implement the Measurable interface, it must also have a public access level, which is stronger than the default package access level. Therefore, changing the access level of the getMeasure method from default to public will resolve the compiler error.

Consider the Following Code Snippet