The code below will not compile successfully unless the argument to the makeMenuItem method is final. Why not?
Public JMenuItem makeMenuItem(final String menuLabel)
{
JMenuItem mi = new JMenuItem(menuLabel);
Class MyMenuListener implements ActionListener
{
Public void actionPerformed(ActionEvent
A) JMenuItem labels must be final
B) This prevents the menuLabel argument from being modified
C) Because a local variable is being accessed from an inner classes
D) Because the String class is final
E) {
DoSomethingElse();
System.out.println(menuLabel);
}
}
Mi)addActionListener(new MyMenuListener());
Return mi;
}

Question

Quizplus · Accepted Answer

Local variables accessed from within an inner class must be final or effectively final in Java. This is because the inner class may be instantiated after the method has completed, and the local variable would no longer exist. Making it final ensures its value remains constant.

The Code Below Will Not Compile Successfully Unless the Argument