Consider the recursive method myPrint in this code snippet:
Public void myPrint(int n)
{
If (n

Question

Consider the recursive method myPrint in this code snippet:
Public void myPrint(int n)
{
If (n < 10)
{
System.out.print(n);
}
Else
{
Int m = n % 10;
System.out.print(m);
MyPrint(n / 10);
}
}
What is printed for the call myPrint(821)?
A) 821
B) 128
C) 12
D) 10

Quizplus · Accepted Answer

When the method myPrint(821) is called, the else block is executed. The integer variable m contains the value 1 because 821 % 10 = 1. The myPrint method is then called recursively, this time with the argument n/10, which is 82. This recursive call will again execute the else block, with m containing the value 2 (82 % 10 = 2), and the method being called recursively again with the argument 8. This final recursive call will trigger the if block, with the integer value 8 being printed. Therefore, the overall output will be 128.

Consider the Recursive Method MyPrint in This Code Snippet