In a hypothetical situation, B is the allele that causes brachydactyly. If a man who has normal fingers (bb) and a woman with brachydactyly (Bb) have children, what proportion of these children would you expect to have normal fingers? (Hint: Use a Punnett square).
A) None
B) All
C) 1/4
D) 3/4
E) 1/2

Question

Quizplus · Accepted Answer

Using a Punnett square, the cross between a bb (normal fingers) and Bb (brachydactyly) individual would result in offspring genotypes of Bb and bb. Half of the children (1/2) are expected to have normal fingers (bb).

In a Hypothetical Situation, B Is the Allele That Causes