Three resistors, 80 $\Omega$, 40 $\Omega$, and 60 $\Omega$, are wired in series and connected to a 120-V battery. How much current flows in this circuit?

Question

Quizplus · Accepted Answer

Using Ohm's law (V = IR), we can find the total resistance of the circuit:
R = 80 + 40 + 60 = 180 ohms

Then, using Ohm's law again, we can find the current:
I = V/R = 120/180 = 0.67 A or 0.67 F1F1F1S1F1F1F10. Therefore, the correct answer is A.

Three Resistors, 80 Ω\OmegaΩ , 40 Ω\OmegaΩ , and 60 Ω\OmegaΩ , Are Wired in Series and Connected to a 120-V

Three Resistors, 80 $\Omega$ , 40 $\Omega$ , and 60 $\Omega$ , Are Wired in Series and Connected to a 120-V