The mating of an Xg+ man with an Xg- woman would produce a son with what phenotype?

Question

Quizplus · Accepted Answer

The Xg+ man is hemizygous for the Xg gene, meaning he only has one allele for Xg, which is Xg(a+). The Xg- woman is homozygous recessive for the Xg gene, meaning she has two alleles for Xg, both of which are Xg(a-). Therefore, their offspring will inherit one X chromosome from each parent, and the son will inherit the Xg(a+) allele from his father and the Xg(a-) allele from his mother. This would make him heterozygous for the Xg gene (Xg(a)/Xg(a-)), resulting in the Xg(a-) phenotype.

The Mating of an Xg+ Man with an Xg- Woman