Sodium chlorate is used as an oxidizer in the manufacture of dyes, explosives, and matches. Calculate the mass of solute needed to prepare 1.575 L of 0.00250 M NaClO₃( = 106.45 g/mol).

Question

Quizplus · Accepted Answer

We can use the formula:

mass = moles x molar mass

First, let's calculate the number of moles of NaClO3 needed:

moles = M x V
      = 0.00250 mol/L x 1.575 L
      = 0.00394 mol

Next, let's calculate the mass of NaClO3 needed:

mass = moles x molar mass
     = 0.00394 mol x 106.45 g/mol
     = 0.419 g

Therefore, the mass of NaClO3 needed to prepare 1.575 L of 0.00250 M NaClO3 is 0.419 g, which is answer choice C.

Sodium Chlorate Is Used as an Oxidizer in the Manufacture