Sulfuric acid (H₂SO₄) reacts with potassium hydroxide (KOH) as follows.
H₂SO₄(aq) + 2KOH(aq) $\to$ K₂SO₄(aq) + 2H₂O(l)
Calculate the volume of 0.100 M sulfuric acid required to neutralize 25.0 mL of 0.0821 M KOH. Show all your work.

Question

Sulfuric acid (H₂SO₄) reacts with potassium hydroxide (KOH) as follows.
H₂SO₄(aq) + 2KOH(aq)

\to

K₂SO₄(aq) + 2H₂O(l)
Calculate the volume of 0.100 M sulfuric acid required to neutralize 25.0 mL of 0.0821 M KOH. Show all your work.

Quizplus · Accepted Answer

The Answer of Sulfuric acid (H₂SO₄) reacts with potassium hydroxide (KOH) as follows. H₂SO₄(aq) + 2KOH(aq) $\to$K₂SO₄(aq) + 2H₂O(l) Calculate the volume of 0.100 M sulfuric acid required to neutralize 25.0 mL of 0.0821 M KOH. Show all your work.

Sulfuric Acid (H2SO4) Reacts with Potassium Hydroxide (KOH) as Follows →\to→

Sulfuric Acid (H₂SO₄) Reacts with Potassium Hydroxide (KOH) as Follows $\to$