The compound carbon suboxide, C₃O₂, is a gas at room temperature. Use the data supplied to calculate the heat of formation of carbon suboxide.
(Data: 2CO(g) + C(s) $\to$ C₃O₂(g) $\Delta$ H° = 127.3 kJ/mol
And: $\Delta$ H_f^° of CO(g) = -110.5 kJ/mol)

Question

The compound carbon suboxide, C₃O₂, is a gas at room temperature. Use the data supplied to calculate the heat of formation of carbon suboxide.
(Data: 2CO(g) + C(s)

\to

C₃O₂(g)

\Delta

H° = 127.3 kJ/mol
And:

\Delta

H_f^° of CO(g) = -110.5 kJ/mol)

Quizplus · Accepted Answer

The heat of formation of carbon suboxide can be calculated using the equation: ΔH° = ΔH°f(C3O2) - [2 * ΔH°f(CO) + ΔH°f(C)]. Solving for ΔH°f(C3O2) gives -93.7 kJ/mol.

The Compound Carbon Suboxide, C3O2, Is a Gas at Room →\to→

The Compound Carbon Suboxide, C₃O₂, Is a Gas at Room $\to$