Which of the following molecules has a plane of symmetry? $$\begin{array}{l}
\begin{array} { l l l l }
\text {$\mathrm { CHBrClF }$}&
\text {$\mathrm { CH } _ { 2 } \mathrm { BrCl }$}&
\text {$\mathrm { CH } _ { 3 } \mathrm { CHClBr }$}&
\text {$\mathrm { CH } _ { 3 } \mathrm { CH } _ { 2 } \mathrm { CHBrF }$}\
I&II&III&IV
\end{array}
\end{array}$$

Question

Which of the following molecules has a plane of symmetry? $$\begin{array}{l}
\begin{array} { l l l l } 
\text {$\mathrm { CHBrClF }$}&
\text {$\mathrm { CH } _ { 2 } \mathrm { BrCl }$}&
\text {$\mathrm { CH } _ { 3 } \mathrm { CHClBr }$}&
\text {$\mathrm { CH } _ { 3 } \mathrm { CH } _ { 2 } \mathrm { CHBrF }$}\
I&II&III&IV
\end{array}
\end{array}$$

Quizplus · Accepted Answer

CH₂BrCl (II) has a plane of symmetry because the two hydrogen atoms are identical, allowing for a mirror plane through the carbon atom and the two hydrogen atoms.

Which of the Following Molecules Has a Plane of Symmetry