Arrange the following amines in order of decreasing water solubility, putting the most soluble amine first.

Question

Quizplus · Accepted Answer

The order of decreasing water solubility for amines is based on their ability to form hydrogen bonds with water molecules. Amine II has the highest water solubility because it is a primary amine and can form two hydrogen bonds with water molecules. Amine I is a secondary amine and can only form one hydrogen bond with water molecules, making it less soluble than amine II. Amine III is a tertiary amine and cannot form any hydrogen bonds with water molecules because it lacks a hydrogen atom bonded to the nitrogen atom. Therefore, the correct order of decreasing water solubility is II > I > III.

Arrange the Following Amines in Order of Decreasing Water Solubility