Rank the following conjugate bases in order of decreasing basicity, putting the most basic first. $$\begin{array} {llll}\mathrm { H } _ { 2 } \mathrm { C } = ^\Theta { \mathrm { CH } }&\mathrm { HC} \equiv \mathrm {^\Theta C }&^\Theta _ { \mathrm { CH } _ { 3 } }\
\text { I }&\text { II } &\text { III } \ \end{array}$$

Question

Rank the following conjugate bases in order of decreasing basicity, putting the most basic first. $$\begin{array} {llll}\mathrm { H } _ { 2 } \mathrm { C } = ^\Theta  { \mathrm { CH } }&\mathrm { HC} \equiv \mathrm {^\Theta  C }&^\Theta _ { \mathrm { CH } _ { 3 } }\
\text { I }&\text { II } &\text { III } \ \end{array}$$

Quizplus · Accepted Answer

The basicity of a conjugate base is inversely related to the acidity of its conjugate acid. The conjugate acid of III (CH4) is the least acidic, making III the most basic. The conjugate acid of I (C2H4) is less acidic than that of II (C2H2), making I more basic than II. Thus, the order is III > I > II.

Rank the Following Conjugate Bases in Order of Decreasing Basicity