In a population at Hardy-Weinberg equilibrium with only two alleles at locus A, the frequency of A alleles is 0.1.The frequency of heterozygotes for this allele is
A) 0.01.
B) 0.02.
C) 0.09.
D) 0.18.
E) 0.50.

Question

Quizplus · Accepted Answer

The frequency of heterozygotes in a Hardy-Weinberg population is given by 2pq, where p is the frequency of one allele (A in this case, 0.1) and q is the frequency of the other allele (q = 1 - p = 0.9). Thus, 2pq = 2 * 0.1 * 0.9 = 0.18.

In a Population at Hardy-Weinberg Equilibrium with Only Two Alleles