Two ice skaters of identical mass approach on parallel paths 1.6 m apart.Both are moving at 3.0 m/s.They join hands as they pass,maintaining their 1.6 m separation,and begin rotating about each other.What is their angular speed?

Question

Quizplus · Accepted Answer

Explanation:The angular speed is given by:ω = v/rwhere v is the linear speed and r is the radius of rotation.In this case, v = 3.0 m/s and r = 1.6 m/2 = 0.8 m.Therefore, ω = 3.0 m/s / 0.8 m = 3.75 rad/s.

Two Ice Skaters of Identical Mass Approach on Parallel Paths