A 1.4 kg object at x = 2.00 m,y = 3.10 m moves at 4.62 m/s at an angle 45° north of east.Calculate the magnitude of the object's angular momentum about the origin.

Question

Quizplus · Accepted Answer

The angular momentum of an object about a point is given by the cross product of its position vector and its momentum vector. In this case, the position vector is r = (2.00 m, 3.10 m) and the momentum vector is p = 1.4 kg * 4.62 m/s at an angle 45° north of east. The magnitude of the angular momentum is then:L = |r x p| = |(2.00 m, 3.10 m) x (1.4 kg * 4.62 m/s at 45° north of east)| = 5.0 kg∙ m2/s

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