-A 100 kg nonuniform boom,6.0 m long,is loosely pinned at the pivot at P.A 600 kg block is suspended from the end of the boom at A.The boom forms a 30° angle with the horizontal,and is supported by a cable,4.0 m long,between points D and B.Point B is 4.0 m from P,and point D is 4.0 m above P.The center of mass of the boom is at point C,which is 2.0 m from P.In the figure,the tension in the cable is closest to:
A)9300 N
B)8400 N
C)8100 N
D)7500 N
E)6900 N

Question

-A 100 kg nonuniform boom,6.0 m long,is loosely pinned at the pivot at P.A 600 kg block is suspended from the end of the boom at A.The boom forms a 30° angle with the horizontal,and is supported by a cable,4.0 m long,between points D and B.Point B is 4.0 m from P,and point D is 4.0 m above P.The center of mass of the boom is at point C,which is 2.0 m from P.In the figure,the tension in the cable is closest to:
A)9300 N 
B)8400 N 
C)8100 N 
D)7500 N 
E)6900 N

Quizplus · Accepted Answer

The tension in the cable can be calculated using the principles of static equilibrium. By resolving forces and taking moments about the pivot point P, the tension in the cable is found to be closest to 9300 N.

-A 100 Kg Nonuniform Boom,6