A spring stretches by 21.0 cm when a 135 N object is attached.What is the weight of a fish that would stretch the spring by 44.9 cm?
A)289 N
B)63 N
C)176 N
D)405 N

Question

Quizplus · Accepted Answer

The spring constant (k) can be calculated using Hooke's Law: F = kx. For the 135 N object, k = 135 N / 0.21 m. Using this k, the weight of the fish is found by F = k * 0.449 m, which equals approximately 289 N.

A Spring Stretches by 21