The engine of a 1250 kg car provides a forward directed force of 3651 N.If the car accelerates at a rate of 2.60 m/s²,what is the total resistive force (wind resistance,friction,etc. )acting on the car? A)401 N B)8600 N C)2400 N D)485 N

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Quizplus · Accepted Answer

The net force is the product of mass and acceleration: F_net = 1250 kg * 2.60 m/s² = 3250 N. The resistive force is the difference between the engine force and the net force: 3651 N - 3250 N = 401 N.

The Engine of a 1250 Kg Car Provides a Forward