Jordan ran up the hill at 7.0 m/s.The horizontal component of Jordan's velocity vector was 1.8 m/s.What was the angle of the hill?
A)75 degrees
B)57 degrees
C)33 degrees
D)15 degrees

Question

Quizplus · Accepted Answer

The angle of the hill can be found using the arctangent function:```θ = arctan(horizontal component of velocity / vertical component of velocity)```In this case, the horizontal component of velocity is 1.8 m/s and the vertical component of velocity is 7.0 m/s, so:```θ = arctan(1.8 m/s / 7.0 m/s) = 15 degrees```Therefore, the angle of the hill is 15 degrees.

Jordan Ran Up the Hill at 7