A cat leaps to catch a bird.If the cat's jump was at 60.0° off the ground and its initial velocity was 2.74 m/s,what is the highest point of its trajectory?

Question

Quizplus · Accepted Answer

The vertical component of the initial velocity is $ v_{0y} = 2.74 \sin(60^\circ) $. Using the formula for maximum height $ h = \frac{v_{0y}^2}{2g} $, where $ g = 9.81 \, \text{m/s}^2 $, the highest point is approximately 0.29 m.

A Cat Leaps to Catch a Bird