A football kicker is attempting a field goal from 44 m out.The ball is kicked and just clears the lower bar with a time of flight of 2.9 s.If the angle of the kick was 45°,what was the initial speed of the ball?
A)21.5 m/s
B)19.7 m/s
C)2.2 m/s
D)39 m/s

Question

Quizplus · Accepted Answer

The horizontal distance (range) covered by the ball is 44 m, and the time of flight is 2.9 s. Using the formula for range R = (v^2 * sin(2θ)) / g, where θ = 45° and g = 9.8 m/s², we can solve for the initial speed v. The horizontal component of velocity is v * cos(θ), and since θ = 45°, cos(θ) = sin(θ) = √2/2. The horizontal distance is also given by v * cos(θ) * time. Solving for v gives approximately 21.5 m/s.

A Football Kicker Is Attempting a Field Goal from 44