An aircraft performs a maneuver called an aileron roll.During this maneuver,the plane turns like a screw as it maintains a straight flight path,by using its ailerons to set the wings in circular motion.Due to structural strength,an airplane can only withstand an acceleration of 6.1 m/s² on its wing tips.If the wing span is 6.0 m,what is the shortest time it can make a full turn when it performs an aileron roll? A)4.4 s B)6.0 s C)0.70 s D)6.2 s

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The centripetal acceleration of the wing tips is given by:$$a_c = v^2/r$$where:* $a_c$ is the centripetal acceleration* $v$ is the speed of the wing tips* $r$ is the radius of the circleThe radius of the circle is half the wingspan, or 3.0 m. The maximum centripetal acceleration that the airplane can withstand is 6.1 m/s^2. Therefore, the speed of the wing tips is:$$v = \sqrt{a_c r} = \sqrt{6.1 \text{ m/s}^2 \cdot 3.0 \text{ m}} = 4.4 \text{ m/s}$$The time it takes to make a full turn is:$$t = 2\pi r/v = 2\pi \cdot 3.0 \text{ m} / 4.4 \text{ m/s} = 4.4 \text{ s}$$

An Aircraft Performs a Maneuver Called an Aileron Roll