Find the wavelength (in nm)of a 6.32 eV photon.

Question

Quizplus · Accepted Answer

The energy of a photon is given by E = hc/λ, where E is the energy in joules, h is Planck's constant (6.63 x 10^-34 J s), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength in meters. To convert the energy from eV to joules, we multiply by the elementary charge (1.6 x 10^-19 J/eV). So, for a 6.32 eV photon, the energy is:E = (6.32 eV) x (1.6 x 10^-19 J/eV) = 1.01 x 10^-18 JNow we can solve for the wavelength:λ = hc/E = (6.63 x 10^-34 J s) x (3 x 10^8 m/s) / (1.01 x 10^-18 J) = 196 nmTherefore, the wavelength of a 6.32 eV photon is 196 nm.

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