You want to confine an electron in a box so that its minimum energy is 5.0 × 10^-18J.What is the length of the box? A)0.11 nm B)0.22 nm C)0.15 nm D)0.18 nm

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The minimum energy of an electron in a box is given by:$$E_n=\frac{n^2h^2}{8mL^2}$$where:* $E_n$ is the energy of the electron in joules* $n$ is the principal quantum number* $h$ is Planck's constant* $m$ is the mass of the electron* $L$ is the length of the boxWe are given that the minimum energy of the electron is $5.0 	imes 10^{-18}$ J. We can use this to solve for the length of the box:$$5.0 	imes 10^{-18} J=\frac{1^2h^2}{8m}$$$$L=\sqrt{\frac{h^2}{8mE_n}}$$$$L=\sqrt{\frac{(6.626 	imes 10^{-34} J \cdot s)^2}{8(9.109 	imes 10^{-31} kg)(5.0 	imes 10^{-18} J)}}$$$$L=0.11 nm$$Therefore, the length of the box is 0.11 nm.

You Want to Confine an Electron in a Box So