Situation 27.1 A proton (rest energy = 938 MeV)has a speed of 0.80 c. -In Situation 27.1,the momentum of the proton in kg ∙ m/s is closest to: A)4.0 × 10^-19 B)4.4 × 10^-19 C)5.0 × 10^-19 D)5.8 × 10^-19 E)6.7 × 10^-19

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The relativistic momentum p is given by p = γmv, where γ = 1/√(1-v²/c²). For v = 0.80c, γ ≈ 1.667. The rest mass m of a proton is 1.67 × 10^-27 kg. Thus, p ≈ 1.667 × 1.67 × 10^-27 kg × 0.80 × 3 × 10^8 m/s ≈ 6.7 × 10^-19 kg∙m/s.

Situation 27.1 a Proton (Rest Energy = 938 MeV)has a Speed of Speed