Situation 27.1
A proton (rest energy = 938 MeV)has a speed of 0.80 c.
-In Situation 27.1,the momentum of the proton in kg ∙ m/s is closest to:

Question

Quizplus · Accepted Answer

The relativistic momentum p is given by p = γmv, where γ = 1/√(1-v²/c²). For v = 0.80c, γ ≈ 1.667. The rest mass m of a proton is 1.67 × 10^-27 kg. Thus, p ≈ 1.667 × 1.67 × 10^-27 kg × 0.80 × 3 × 10^8 m/s ≈ 6.7 × 10^-19 kg∙m/s.

Situation 27.1 a Proton (Rest Energy = 938 MeV)has a Speed of Speed