An RLC circuit has a sinusoidal voltage supplied to it at 632 kHz with a peak voltage of 748 V;a 25 kΩ resistance;a 16 μF capacitance;and a 30 H inductance.What is the peak current for this circuit?

Question

Quizplus · Accepted Answer

The peak current in an RLC circuit is given by:Ip = Vp / (sqrt(R^2 + (XL - XC)^2))where Vp is the peak voltage, R is the resistance, XL is the inductive reactance, and XC is the capacitive reactance.In this case, Vp = 748 V, R = 25 kΩ, XL = 2πfL = 2π(632 kHz)(30 H) = 38.6 kΩ, and XC = 1 / (2πfC) = 1 / (2π(632 kHz)(16 μF)) = 20.1 kΩ.Therefore, Ip = 748 V / (sqrt((25 kΩ)^2 + (38.6 kΩ - 20.1 kΩ)^2)) = 6.3 μA.

An RLC Circuit Has a Sinusoidal Voltage Supplied to It