Alpha particles (charge = +2e,mass = 6.68 × 10^-27 kg)are accelerated in a cyclotron to a final orbit radius of 0.50 m.The magnetic field in the cyclotron is 0.50 T.The kinetic energy of an alpha particle in the final orbit is closest to: A)3.0 MeV B)2.6 MeV C)3.4 MeV D)3.9 MeV E)4.3 MeV

Question

Quizplus · Accepted Answer

The kinetic energy (KE) of an alpha particle in a cyclotron can be calculated using the formula KE = (q^2 * B^2 * r^2) / (2m), where q is the charge, B is the magnetic field, r is the radius, and m is the mass. Substituting the given values (q = 2e = 2 * 1.6 × 10^-19 C, B = 0.50 T, r = 0.50 m, m = 6.68 × 10^-27 kg) into the formula gives a kinetic energy closest to 3.0 MeV.

Alpha Particles (Charge = +2e,mass = 6