A 5 m length of wire carrying a current of 5 A lies on a horizontal table with a rectangular top of dimensions 0.300 m × 0.400 m.The ends of the wire are attached to opposite ends of a diagonal of the rectangle.A vertical magnetic field of 0.30 T is present.What magnetic force acts on this segment of wire?
A)0.75 N
B)1.1 N
C)7.5 N
D)zero
E)The force cannot be determined without knowing the shape of the length of wire.

Question

Quizplus · Accepted Answer

The magnetic force on a current-carrying wire in a magnetic field is given by F = BIL sin(θ). Here, B = 0.30 T, I = 5 A, L = 5 m, and θ = 90° (since the wire is horizontal and the magnetic field is vertical). Thus, F = 0.30 * 5 * 5 * sin(90°) = 0.75 N.

A 5 M Length of Wire Carrying a Current of 5