A tube of mercury with resistivity 9.84 × 10^-7Ω·m has a 23.0 N/C electric field inside the column of mercury.How much current is flowing,if the diameter of the tube is ?

Question

Quizplus · Accepted Answer

The current flowing in the tube can be calculated using Ohm's law: I = V/R, where V is the potential difference across the tube and R is the resistance of the tube. The potential difference can be calculated using the electric field and the length of the tube: V = Ed, where E is the electric field and d is the length of the tube. The resistance of the tube can be calculated using the resistivity and the dimensions of the tube: R = ρL/A, where ρ is the resistivity, L is the length of the tube, and A is the cross-sectional area of the tube. Substituting these expressions into Ohm's law, we get: I = Ed/ρL/A. Plugging in the given values, we get: I = (23.0 N/C)(0.100 m)/(9.84 × 10^-7 Ω·m)(1.00 m)(π(0.00500 m)^2) = 18 A.

A Tube of Mercury with Resistivity 9