Two like charges of the same magnitude are 5.0 mm apart.If the force of repulsion they exert upon each other is 2.0 N,what is the magnitude of each charge? (The constant of proportionality for the Coulombic force is 9.0 × 10⁹ N·m²/C². ) A)7.5 × 10^-2 C B)7.5 × 10^-8 C C)7.2 × 10² C D)7.5 × 10^-5 C

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Quizplus · Accepted Answer

Using Coulomb's law, F = k * (q1 * q2) / r^2, where F = 2.0 N, k = 9.0 × 10^9 N·m^2/C^2, and r = 5.0 mm = 5.0 × 10^-3 m. Solving for q (since q1 = q2), we get q = sqrt((F * r^2) / k) = sqrt((2.0 * (5.0 × 10^-3)^2) / (9.0 × 10^9)) = 7.5 × 10^-8 C.

Two Like Charges of the Same Magnitude Are 5